Climbing Beach Mt. NC

[scooter01]

Does anyone know the percent of climb for this road?

I have found it s 3.98 miles long with a 1800" elevation change.
does this calculate out to <10% ?

[97CSI]

(3.98x5280)/1800=11.67%. The math is right, but don't know about the formula.

[sellsworth]

Using a sine function I calculated the angle of the climb in degrees to be 4.914, which converts to a percent grade of 8.697. It's the middle of the summer so I could be way off on this.

[hmbmd]

1800ft/(3.98miles x 5280 ft/mile) = .0856 = 8.56%

[sellsworth]

1800ft/(3.98miles x 5280 ft/mile) = .0856 = 8.56%

In right triangle terms you are taking the ratio of the opposite over the hypotenuse. I don't think that this is the most accurate way to do % grade.

[Too Tall]

"Does anyone know the percent of climb for this road?"

Yeah. STRAIGHT UP :cool:

In a cruel twist, the "engineers" put the "rest spot" only 50 feet from the top...on the uphill. BARSTARDS !!!

[znfdl]

But it is a fun climb. :D

[justinf]

Yeah, it's steep. Don't let the math fool you. It's Beech, btw. Fun riding country for sure.

[Fat Robert]

its a beyotch, not a beech, unless you're cheech.


i'm never going back there again.

[bcm119]

Percent grade is actually rise / horizontal distance, but in this case the horizontal distance is so close to the actual distance traveled (3.98 miles) that the simple division of 1800/(3.98*5280) works fine.

[hmbmd]

using x squared + y squared = z squared for a right angled triangle. y = 1800 and z = 21014.4 ft (3.98 miles) then x calculates to 20937.16 ft. The grade then is 1800/20936.15 which equlas 8.597% which is very close to my earlier answer.

[scooter01]

Thanks guys!

I could not find anything on the web for this road. Its suppose to be one of LA favorites.

This is where the Cycle North Carolina ride start s this year. Then it's all down hill to the coast. (yeah, right)

I think 8-10 % sounds about right for the average.

[sellsworth]

Percent grade is actually rise / horizontal distance, but in this case the horizontal distance is so close to the actual distance traveled (3.98 miles) that the simple division of 1800/(3.98*5280) works fine.

This works OK on the longer and not so steep climbs when the base is similar to the hypotenuse. On short and steep climbs the base and hypotenuse are different enough so that the % gradient estimates could be off significantly.